3.3.23 \(\int \frac {1}{-x^3+b x^5} \, dx\)

Optimal. Leaf size=27 \[ \frac {1}{2} b \log \left (1-b x^2\right )-b \log (x)+\frac {1}{2 x^2} \]

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Rubi [A]  time = 0.02, antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {1593, 266, 44} \begin {gather*} \frac {1}{2} b \log \left (1-b x^2\right )-b \log (x)+\frac {1}{2 x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(-x^3 + b*x^5)^(-1),x]

[Out]

1/(2*x^2) - b*Log[x] + (b*Log[1 - b*x^2])/2

Rule 44

Int[((a_) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d*
x)^n, x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, 0] && IntegerQ[n] &&  !(IGtQ[n, 0] && L
tQ[m + n + 2, 0])

Rule 266

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rule 1593

Int[(u_.)*((a_.)*(x_)^(p_.) + (b_.)*(x_)^(q_.))^(n_.), x_Symbol] :> Int[u*x^(n*p)*(a + b*x^(q - p))^n, x] /; F
reeQ[{a, b, p, q}, x] && IntegerQ[n] && PosQ[q - p]

Rubi steps

\begin {align*} \int \frac {1}{-x^3+b x^5} \, dx &=\int \frac {1}{x^3 \left (-1+b x^2\right )} \, dx\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \frac {1}{x^2 (-1+b x)} \, dx,x,x^2\right )\\ &=\frac {1}{2} \operatorname {Subst}\left (\int \left (-\frac {1}{x^2}-\frac {b}{x}+\frac {b^2}{-1+b x}\right ) \, dx,x,x^2\right )\\ &=\frac {1}{2 x^2}-b \log (x)+\frac {1}{2} b \log \left (1-b x^2\right )\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 27, normalized size = 1.00 \begin {gather*} \frac {1}{2} b \log \left (1-b x^2\right )-b \log (x)+\frac {1}{2 x^2} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(-x^3 + b*x^5)^(-1),x]

[Out]

1/(2*x^2) - b*Log[x] + (b*Log[1 - b*x^2])/2

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{-x^3+b x^5} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[(-x^3 + b*x^5)^(-1),x]

[Out]

IntegrateAlgebraic[(-x^3 + b*x^5)^(-1), x]

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fricas [A]  time = 0.39, size = 28, normalized size = 1.04 \begin {gather*} \frac {b x^{2} \log \left (b x^{2} - 1\right ) - 2 \, b x^{2} \log \relax (x) + 1}{2 \, x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^5-x^3),x, algorithm="fricas")

[Out]

1/2*(b*x^2*log(b*x^2 - 1) - 2*b*x^2*log(x) + 1)/x^2

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giac [A]  time = 0.18, size = 32, normalized size = 1.19 \begin {gather*} -\frac {1}{2} \, b \log \left (x^{2}\right ) + \frac {1}{2} \, b \log \left ({\left | b x^{2} - 1 \right |}\right ) + \frac {b x^{2} + 1}{2 \, x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^5-x^3),x, algorithm="giac")

[Out]

-1/2*b*log(x^2) + 1/2*b*log(abs(b*x^2 - 1)) + 1/2*(b*x^2 + 1)/x^2

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maple [A]  time = 0.05, size = 23, normalized size = 0.85 \begin {gather*} -b \ln \relax (x )+\frac {b \ln \left (b \,x^{2}-1\right )}{2}+\frac {1}{2 x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x^5-x^3),x)

[Out]

1/2*b*ln(b*x^2-1)+1/2/x^2-b*ln(x)

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maxima [A]  time = 1.32, size = 22, normalized size = 0.81 \begin {gather*} \frac {1}{2} \, b \log \left (b x^{2} - 1\right ) - b \log \relax (x) + \frac {1}{2 \, x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^5-x^3),x, algorithm="maxima")

[Out]

1/2*b*log(b*x^2 - 1) - b*log(x) + 1/2/x^2

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mupad [B]  time = 5.21, size = 22, normalized size = 0.81 \begin {gather*} \frac {b\,\ln \left (b\,x^2-1\right )}{2}-b\,\ln \relax (x)+\frac {1}{2\,x^2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x^5 - x^3),x)

[Out]

(b*log(b*x^2 - 1))/2 - b*log(x) + 1/(2*x^2)

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sympy [A]  time = 0.23, size = 22, normalized size = 0.81 \begin {gather*} - b \log {\relax (x )} + \frac {b \log {\left (x^{2} - \frac {1}{b} \right )}}{2} + \frac {1}{2 x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x**5-x**3),x)

[Out]

-b*log(x) + b*log(x**2 - 1/b)/2 + 1/(2*x**2)

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